x^2-110x+1500=0

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Solution for x^2-110x+1500=0 equation:



x^2-110x+1500=0
a = 1; b = -110; c = +1500;
Δ = b2-4ac
Δ = -1102-4·1·1500
Δ = 6100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{6100}=\sqrt{100*61}=\sqrt{100}*\sqrt{61}=10\sqrt{61}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-110)-10\sqrt{61}}{2*1}=\frac{110-10\sqrt{61}}{2} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-110)+10\sqrt{61}}{2*1}=\frac{110+10\sqrt{61}}{2} $

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